This is a simple design circuit for touch switch circuit. This circuit is built using CD4011 ICs. The IC CD4011 is wires as a flip flop here. This is a figure of the circuit.
This is explanation about principle work of the circuit. The 9, 13 pins of the IC works as the set and reset contacts respectively. CMOS ICs like 4011 require requires a very low current for controlling its gates. Since the pins 9 and 13 are connected to the positive via resistors R1 and R2, the logic gates of the ICs will be in high state. When we touch through the points A, B the gates of the IC will be closed and the output becomes low. This switches ON the transistor Q1 and the relay gets activated. When we touch through the points C, D the gates again becomes high and switches the transistor OFF. This makes the relay OFF. Thus by touching through the contact points A, B and C, D the appliance connected through the relay can be switched On and OFF. The relay can be a 12 V, 200 Ohm SPDT relay. The circuit is needed a power supply 12V DC for powering the operation.
This is explanation about principle work of the circuit. The 9, 13 pins of the IC works as the set and reset contacts respectively. CMOS ICs like 4011 require requires a very low current for controlling its gates. Since the pins 9 and 13 are connected to the positive via resistors R1 and R2, the logic gates of the ICs will be in high state. When we touch through the points A, B the gates of the IC will be closed and the output becomes low. This switches ON the transistor Q1 and the relay gets activated. When we touch through the points C, D the gates again becomes high and switches the transistor OFF. This makes the relay OFF. Thus by touching through the contact points A, B and C, D the appliance connected through the relay can be switched On and OFF. The relay can be a 12 V, 200 Ohm SPDT relay. The circuit is needed a power supply 12V DC for powering the operation.
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